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113433001 = 1110312091
BaseRepresentation
bin1101100001011…
…01100110101001
321220102222211021
412300231212221
5213014324001
615131132441
72545110313
oct660554651
9256388737
10113433001
1159036990
1231ba4121
131a667b26
14110ca7b3
159e59ba1
hex6c2d9a9

113433001 has 4 divisors (see below), whose sum is σ = 123745104. Its totient is φ = 103120900.

The previous prime is 113432953. The next prime is 113433037. The reversal of 113433001 is 100334311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113433001 - 213 = 113424809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113433041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5156035 + ... + 5156056.

It is an arithmetic number, because the mean of its divisors is an integer number (30936276).

Almost surely, 2113433001 is an apocalyptic number.

113433001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

113433001 is a deficient number, since it is larger than the sum of its proper divisors (10312103).

113433001 is a wasteful number, since it uses less digits than its factorization.

113433001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10312102.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 113433001 is about 10650.4929932844. The cubic root of 113433001 is about 484.0755423035.

Adding to 113433001 its reverse (100334311), we get a palindrome (213767312).

The spelling of 113433001 in words is "one hundred thirteen million, four hundred thirty-three thousand, one".

Divisors: 1 11 10312091 113433001