Base | Representation |
---|---|
bin | 110100110100100100… |
… | …1000011100111110111 |
3 | 101211210100110010110000 |
4 | 1221221021003213313 |
5 | 3324302340202021 |
6 | 124035505402343 |
7 | 11123656465140 |
oct | 1515111034767 |
9 | 354710403400 |
10 | 113433131511 |
11 | 4411a055687 |
12 | 19b986393b3 |
13 | a90985317b |
14 | 56c1136ac7 |
15 | 2e3d6e6b26 |
hex | 1a692439f7 |
113433131511 has 40 divisors (see below), whose sum is σ = 194371426304. Its totient is φ = 64579660560.
The previous prime is 113433131467. The next prime is 113433131521. The reversal of 113433131511 is 115131334311.
113433131511 is a `hidden beast` number, since 1 + 1 + 3 + 4 + 331 + 315 + 11 = 666.
It is not a de Polignac number, because 113433131511 - 221 = 113431034359 is a prime.
It is a super-2 number, since 2×1134331315112 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113433131521) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 215455 + ... + 522768.
Almost surely, 2113433131511 is an apocalyptic number.
113433131511 is a deficient number, since it is larger than the sum of its proper divisors (80938294793).
113433131511 is an equidigital number, since it uses as much as digits as its factorization.
113433131511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 738513 (or 738504 counting only the distinct ones).
The product of its digits is 1620, while the sum is 27.
Adding to 113433131511 its reverse (115131334311), we get a palindrome (228564465822).
The spelling of 113433131511 in words is "one hundred thirteen billion, four hundred thirty-three million, one hundred thirty-one thousand, five hundred eleven".
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