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113433135 = 3519398011
BaseRepresentation
bin1101100001011…
…01101000101111
321220110000000020
412300231220233
5213014330020
615131133223
72545110564
oct660555057
9256400006
10113433135
1159036aa2
1231ba4213
131a667bca
14110ca86b
159e59c40
hex6c2da2f

113433135 has 16 divisors (see below), whose sum is σ = 191045760. Its totient is φ = 57313440.

The previous prime is 113433127. The next prime is 113433143. The reversal of 113433135 is 531334311.

It is an interprime number because it is at equal distance from previous prime (113433127) and next prime (113433143).

It is not a de Polignac number, because 113433135 - 23 = 113433127 is a prime.

It is a super-2 number, since 2×1134331352 = 25734152231856450, which contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 198721 + ... + 199290.

It is an arithmetic number, because the mean of its divisors is an integer number (11940360).

Almost surely, 2113433135 is an apocalyptic number.

113433135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

113433135 is a deficient number, since it is larger than the sum of its proper divisors (77612625).

113433135 is a wasteful number, since it uses less digits than its factorization.

113433135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 398038.

The product of its digits is 1620, while the sum is 24.

The square root of 113433135 is about 10650.4992840711. The cubic root of 113433135 is about 484.0757329185.

Adding to 113433135 its reverse (531334311), we get a palindrome (644767446).

The spelling of 113433135 in words is "one hundred thirteen million, four hundred thirty-three thousand, one hundred thirty-five".

Divisors: 1 3 5 15 19 57 95 285 398011 1194033 1990055 5970165 7562209 22686627 37811045 113433135