Base | Representation |
---|---|
bin | 10000100000011011111… |
… | …011101111100010000011 |
3 | 11000102221002212010120002 |
4 | 100200123323233202003 |
5 | 122041112020342123 |
6 | 2225035243110215 |
7 | 144645001005041 |
oct | 20403373574203 |
9 | 4012832763502 |
10 | 1134340012163 |
11 | 3a8086401436 |
12 | 163a1421236b |
13 | 82c7735bab7 |
14 | 3cc8c093391 |
15 | 1e790614528 |
hex | 1081beef883 |
1134340012163 has 2 divisors, whose sum is σ = 1134340012164. Its totient is φ = 1134340012162.
The previous prime is 1134340012153. The next prime is 1134340012171. The reversal of 1134340012163 is 3612100434311.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3612100434311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1134340012163 - 28 = 1134340011907 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134340012133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567170006081 + 567170006082.
It is an arithmetic number, because the mean of its divisors is an integer number (567170006082).
Almost surely, 21134340012163 is an apocalyptic number.
1134340012163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134340012163 is an equidigital number, since it uses as much as digits as its factorization.
1134340012163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 1134340012163 its reverse (3612100434311), we get a palindrome (4746440446474).
The spelling of 1134340012163 in words is "one trillion, one hundred thirty-four billion, three hundred forty million, twelve thousand, one hundred sixty-three".
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