113434011433 has 2 divisors, whose sum is σ = 113434011434. Its totient is φ = 113434011432.

The previous prime is 113434011421. The next prime is 113434011461. The reversal of 113434011433 is 334110434311.

It is an a-pointer prime, because the next prime (113434011461) can be obtained adding 113434011433 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99065674009 + 14368337424 = 314747^2 + 119868^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113434011433 is a prime.

It is not a weakly prime, because it can be changed into another prime (113434011403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56717005716 + 56717005717.

It is an arithmetic number, because the mean of its divisors is an integer number (56717005717).

Almost surely, 2^113434011433 is an apocalyptic number.

It is an amenable number.

113434011433 is a deficient number, since it is larger than the sum of its proper divisors (1).

113434011433 is an equidigital number, since it uses as much as digits as its factorization.

113434011433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 113434011433 its reverse (334110434311), we get a palindrome (447544445744).

The spelling of 113434011433 in words is "one hundred thirteen billion, four hundred thirty-four million, eleven thousand, four hundred thirty-three".