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113434130041 = 367773399851
BaseRepresentation
bin110100110100100110…
…0110111011001111001
3101211210102022212011121
41221221030313121321
53324303114130131
6124035543025241
711124001124251
oct1515114673171
9354712285147
10113434130041
114411a677911
1219b98a3b221
13a909b1280b
1456c1316961
152e3d842911
hex1a69337679

113434130041 has 8 divisors (see below), whose sum is σ = 113890644864. Its totient is φ = 112978417200.

The previous prime is 113434130021. The next prime is 113434130101. The reversal of 113434130041 is 140031434311.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113434130041 - 211 = 113434127993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113434129988 and 113434130015.

It is not an unprimeable number, because it can be changed into a prime (113434130021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83766 + ... + 483616.

It is an arithmetic number, because the mean of its divisors is an integer number (14236330608).

Almost surely, 2113434130041 is an apocalyptic number.

It is an amenable number.

113434130041 is a deficient number, since it is larger than the sum of its proper divisors (456514823).

113434130041 is an equidigital number, since it uses as much as digits as its factorization.

113434130041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400991.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 113434130041 its reverse (140031434311), we get a palindrome (253465564352).

The spelling of 113434130041 in words is "one hundred thirteen billion, four hundred thirty-four million, one hundred thirty thousand, forty-one".

Divisors: 1 367 773 283691 399851 146745317 309084823 113434130041