Base | Representation |
---|---|
bin | 110100110100100110… |
… | …0110111011001111001 |
3 | 101211210102022212011121 |
4 | 1221221030313121321 |
5 | 3324303114130131 |
6 | 124035543025241 |
7 | 11124001124251 |
oct | 1515114673171 |
9 | 354712285147 |
10 | 113434130041 |
11 | 4411a677911 |
12 | 19b98a3b221 |
13 | a909b1280b |
14 | 56c1316961 |
15 | 2e3d842911 |
hex | 1a69337679 |
113434130041 has 8 divisors (see below), whose sum is σ = 113890644864. Its totient is φ = 112978417200.
The previous prime is 113434130021. The next prime is 113434130101. The reversal of 113434130041 is 140031434311.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113434130041 - 211 = 113434127993 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113434129988 and 113434130015.
It is not an unprimeable number, because it can be changed into a prime (113434130021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83766 + ... + 483616.
It is an arithmetic number, because the mean of its divisors is an integer number (14236330608).
Almost surely, 2113434130041 is an apocalyptic number.
It is an amenable number.
113434130041 is a deficient number, since it is larger than the sum of its proper divisors (456514823).
113434130041 is an equidigital number, since it uses as much as digits as its factorization.
113434130041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 400991.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 113434130041 its reverse (140031434311), we get a palindrome (253465564352).
The spelling of 113434130041 in words is "one hundred thirteen billion, four hundred thirty-four million, one hundred thirty thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •