Base | Representation |
---|---|
bin | 10101001000001111… |
… | …01100000011000001 |
3 | 1002021112122002220202 |
4 | 22210013230003001 |
5 | 141212403212231 |
6 | 5113332414545 |
7 | 551046265133 |
oct | 124407540301 |
9 | 32245562822 |
10 | 11343413441 |
11 | 48a1074458 |
12 | 2246a77455 |
13 | 10ba115879 |
14 | 798745053 |
15 | 465cc65cb |
hex | 2a41ec0c1 |
11343413441 has 2 divisors, whose sum is σ = 11343413442. Its totient is φ = 11343413440.
The previous prime is 11343413429. The next prime is 11343413467. The reversal of 11343413441 is 14431434311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7440787600 + 3902625841 = 86260^2 + 62471^2 .
It is a cyclic number.
It is not a de Polignac number, because 11343413441 - 210 = 11343412417 is a prime.
It is not a weakly prime, because it can be changed into another prime (11343413941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671706720 + 5671706721.
It is an arithmetic number, because the mean of its divisors is an integer number (5671706721).
Almost surely, 211343413441 is an apocalyptic number.
It is an amenable number.
11343413441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11343413441 is an equidigital number, since it uses as much as digits as its factorization.
11343413441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 29.
Adding to 11343413441 its reverse (14431434311), we get a palindrome (25774847752).
The spelling of 11343413441 in words is "eleven billion, three hundred forty-three million, four hundred thirteen thousand, four hundred forty-one".
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