Base | Representation |
---|---|
bin | 110100110100100110… |
… | …0111100101000001010 |
3 | 101211210102100221111221 |
4 | 1221221030330220022 |
5 | 3324303120321214 |
6 | 124035543312254 |
7 | 11124001243522 |
oct | 1515114745012 |
9 | 354712327457 |
10 | 113434151434 |
11 | 4411a69199a |
12 | 19b98a4b68a |
13 | a909b1c486 |
14 | 56c1320682 |
15 | 2e3d848e24 |
hex | 1a6933ca0a |
113434151434 has 4 divisors (see below), whose sum is σ = 170151227154. Its totient is φ = 56717075716.
The previous prime is 113434151419. The next prime is 113434151447. The reversal of 113434151434 is 434151434311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 434151434311 = 7 ⋅62021633473.
It can be written as a sum of positive squares in only one way, i.e., 72117491209 + 41316660225 = 268547^2 + 203265^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 113434151434.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28358537857 + ... + 28358537860.
Almost surely, 2113434151434 is an apocalyptic number.
113434151434 is a deficient number, since it is larger than the sum of its proper divisors (56717075720).
113434151434 is an equidigital number, since it uses as much as digits as its factorization.
113434151434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56717075719.
The product of its digits is 34560, while the sum is 34.
Adding to 113434151434 its reverse (434151434311), we get a palindrome (547585585745).
The spelling of 113434151434 in words is "one hundred thirteen billion, four hundred thirty-four million, one hundred fifty-one thousand, four hundred thirty-four".
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