Base | Representation |
---|---|
bin | 10101001000001111… |
… | …10001000100101111 |
3 | 1002021112200011011100 |
4 | 22210013301010233 |
5 | 141212404342111 |
6 | 5113333054143 |
7 | 551046412146 |
oct | 124407610457 |
9 | 32245604140 |
10 | 11343434031 |
11 | 48a1088976 |
12 | 2246a87353 |
13 | 10ba122057 |
14 | 79874c75d |
15 | 465ccc756 |
hex | 2a41f112f |
11343434031 has 12 divisors (see below), whose sum is σ = 16452950800. Its totient is φ = 7530909120.
The previous prime is 11343434029. The next prime is 11343434033. The reversal of 11343434031 is 13043434311.
It is an interprime number because it is at equal distance from previous prime (11343434029) and next prime (11343434033).
It is not a de Polignac number, because 11343434031 - 21 = 11343434029 is a prime.
It is a super-2 number, since 2×113434340312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11343433986 and 11343434004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11343434033) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2612731 + ... + 2617068.
Almost surely, 211343434031 is an apocalyptic number.
11343434031 is a deficient number, since it is larger than the sum of its proper divisors (5109516769).
11343434031 is a wasteful number, since it uses less digits than its factorization.
11343434031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5230046 (or 5230043 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 11343434031 its reverse (13043434311), we get a palindrome (24386868342).
The spelling of 11343434031 in words is "eleven billion, three hundred forty-three million, four hundred thirty-four thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •