Base | Representation |
---|---|
bin | 1010010100010001111000… |
… | …0010001010001100001001 |
3 | 1111011102120220001022010221 |
4 | 2211010132002022030021 |
5 | 2441323003200324431 |
6 | 40043045424510041 |
7 | 2250353546305231 |
oct | 245043602121411 |
9 | 44142526038127 |
10 | 11343512511241 |
11 | 36838360a69a9 |
12 | 133254747b321 |
13 | 6438c4c32421 |
14 | 2b305957ccc1 |
15 | 14a10ddce111 |
hex | a511e08a309 |
11343512511241 has 2 divisors, whose sum is σ = 11343512511242. Its totient is φ = 11343512511240.
The previous prime is 11343512511239. The next prime is 11343512511257. The reversal of 11343512511241 is 14211521534311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10274364783225 + 1069147728016 = 3205365^2 + 1033996^2 .
It is a cyclic number.
It is not a de Polignac number, because 11343512511241 - 21 = 11343512511239 is a prime.
Together with 11343512511239, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11343512511197 and 11343512511206.
It is not a weakly prime, because it can be changed into another prime (11343512511211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671756255620 + 5671756255621.
It is an arithmetic number, because the mean of its divisors is an integer number (5671756255621).
Almost surely, 211343512511241 is an apocalyptic number.
It is an amenable number.
11343512511241 is a deficient number, since it is larger than the sum of its proper divisors (1).
11343512511241 is an equidigital number, since it uses as much as digits as its factorization.
11343512511241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 34.
The spelling of 11343512511241 in words is "eleven trillion, three hundred forty-three billion, five hundred twelve million, five hundred eleven thousand, two hundred forty-one".
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