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1134401303003 = 1959705331737
BaseRepresentation
bin10000100000011111100…
…101100011000111011011
311000110002101012000210012
4100200133211203013123
5122041223213144003
62225045312512135
7144646343656403
oct20403745430733
94013071160705
101134401303003
113a8107a64121
12163a3084b64b
1382c86c6b477
143cc96289803
151e795bbe8d8
hex1081f9631db

1134401303003 has 4 divisors (see below), whose sum is σ = 1194106634760. Its totient is φ = 1074695971248.

The previous prime is 1134401302973. The next prime is 1134401303029. The reversal of 1134401303003 is 3003031044311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134401303003 - 26 = 1134401302939 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1134401303003.

It is not an unprimeable number, because it can be changed into a prime (1134401303033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29852665850 + ... + 29852665887.

It is an arithmetic number, because the mean of its divisors is an integer number (298526658690).

Almost surely, 21134401303003 is an apocalyptic number.

1134401303003 is a deficient number, since it is larger than the sum of its proper divisors (59705331757).

1134401303003 is an equidigital number, since it uses as much as digits as its factorization.

1134401303003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59705331756.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1134401303003 its reverse (3003031044311), we get a palindrome (4137432347314).

The spelling of 1134401303003 in words is "one trillion, one hundred thirty-four billion, four hundred one million, three hundred three thousand, three".

Divisors: 1 19 59705331737 1134401303003