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11344013101 = 26591426611
BaseRepresentation
bin10101001000010011…
…11110011100101101
31002021120202120111101
422210021332130231
5141213031404401
65113353323101
7551054343331
oct124411763455
932246676441
1011344013101
1148a1443a43
122247106491
1310ba2957b5
1479885d7c1
15465d94101
hex2a427e72d

11344013101 has 4 divisors (see below), whose sum is σ = 11344466304. Its totient is φ = 11343559900.

The previous prime is 11344013089. The next prime is 11344013111. The reversal of 11344013101 is 10131044311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11344013101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11344013111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186715 + ... + 239896.

It is an arithmetic number, because the mean of its divisors is an integer number (2836116576).

Almost surely, 211344013101 is an apocalyptic number.

It is an amenable number.

11344013101 is a deficient number, since it is larger than the sum of its proper divisors (453203).

11344013101 is an equidigital number, since it uses as much as digits as its factorization.

11344013101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 453202.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11344013101 its reverse (10131044311), we get a palindrome (21475057412).

The spelling of 11344013101 in words is "eleven billion, three hundred forty-four million, thirteen thousand, one hundred one".

Divisors: 1 26591 426611 11344013101