Base | Representation |
---|---|
bin | 1010010100010011101111… |
… | …0111110101101100011111 |
3 | 1111011110212210000222110120 |
4 | 2211010323313311230133 |
5 | 2441330014324403320 |
6 | 40043211230410023 |
7 | 2250402135365625 |
oct | 245047367655437 |
9 | 44143783028416 |
10 | 11344013122335 |
11 | 3683a72740483 |
12 | 1332667060913 |
13 | 64397486c6ca |
14 | 2b30a5c53515 |
15 | 14a13cd18440 |
hex | a513bdf5b1f |
11344013122335 has 32 divisors (see below), whose sum is σ = 18448310184960. Its totient is φ = 5950847606400.
The previous prime is 11344013122319. The next prime is 11344013122349. The reversal of 11344013122335 is 53322131044311.
It is not a de Polignac number, because 11344013122335 - 24 = 11344013122319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11344013122296 and 11344013122305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 79726986 + ... + 79869144.
It is an arithmetic number, because the mean of its divisors is an integer number (576509693280).
Almost surely, 211344013122335 is an apocalyptic number.
11344013122335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11344013122335 is a deficient number, since it is larger than the sum of its proper divisors (7104297062625).
11344013122335 is a wasteful number, since it uses less digits than its factorization.
11344013122335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 229439.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 11344013122335 its reverse (53322131044311), we get a palindrome (64666144166646).
The spelling of 11344013122335 in words is "eleven trillion, three hundred forty-four billion, thirteen million, one hundred twenty-two thousand, three hundred thirty-five".
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