113440143413 has 4 divisors (see below), whose sum is σ = 113453824140. Its totient is φ = 113426462688.

The previous prime is 113440143409. The next prime is 113440143433. The reversal of 113440143413 is 314341044311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 314341044311 = 7 ⋅44905863473.

It can be written as a sum of positive squares in 2 ways, for example, as 110920304209 + 2519839204 = 333047^2 + 50198^2 .

It is a cyclic number.

It is not a de Polignac number, because 113440143413 - 2² = 113440143409 is a prime.

It is a super-2 number, since 2×113440143413² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113440143433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6827918 + ... + 6844511.

It is an arithmetic number, because the mean of its divisors is an integer number (28363456035).

Almost surely, 2^113440143413 is an apocalyptic number.

It is an amenable number.

113440143413 is a deficient number, since it is larger than the sum of its proper divisors (13680727).

113440143413 is an equidigital number, since it uses as much as digits as its factorization.

113440143413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13680726.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 113440143413 its reverse (314341044311), we get a palindrome (427781187724).

The spelling of 113440143413 in words is "one hundred thirteen billion, four hundred forty million, one hundred forty-three thousand, four hundred thirteen".