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1134414332521 is a prime number
BaseRepresentation
bin10000100000100000010…
…111010000001001101001
311000110010021200222220221
4100200200113100021221
5122041240032120041
62225050500050041
7144646562504341
oct20404027201151
94013107628827
101134414332521
113a8114353418
12163a35093921
1382c89880c42
143cc97cbbd21
151e796de52d1
hex108205d0269

1134414332521 has 2 divisors, whose sum is σ = 1134414332522. Its totient is φ = 1134414332520.

The previous prime is 1134414332369. The next prime is 1134414332539. The reversal of 1134414332521 is 1252334144311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1108682643600 + 25731688921 = 1052940^2 + 160411^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1134414332521 is a prime.

It is not a weakly prime, because it can be changed into another prime (1134414332581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567207166260 + 567207166261.

It is an arithmetic number, because the mean of its divisors is an integer number (567207166261).

Almost surely, 21134414332521 is an apocalyptic number.

It is an amenable number.

1134414332521 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134414332521 is an equidigital number, since it uses as much as digits as its factorization.

1134414332521 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 34.

Adding to 1134414332521 its reverse (1252334144311), we get a palindrome (2386748476832).

The spelling of 1134414332521 in words is "one trillion, one hundred thirty-four billion, four hundred fourteen million, three hundred thirty-two thousand, five hundred twenty-one".