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11344221131 = 29391180039
BaseRepresentation
bin10101001000010101…
…10001001111001011
31002021121011010212012
422210022301033023
5141213110034011
65113402010135
7551056200665
oct124412611713
932247133765
1011344221131
1148a1576271
1222471a694b
1310ba3393a9
147988b5535
15465dd5a8b
hex2a42b13cb

11344221131 has 4 divisors (see below), whose sum is σ = 11735401200. Its totient is φ = 10953041064.

The previous prime is 11344221089. The next prime is 11344221139. The reversal of 11344221131 is 13112244311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11344221131 - 26 = 11344221067 is a prime.

It is a super-2 number, since 2×113442211312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11344221097 and 11344221106.

It is not an unprimeable number, because it can be changed into a prime (11344221139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195589991 + ... + 195590048.

It is an arithmetic number, because the mean of its divisors is an integer number (2933850300).

Almost surely, 211344221131 is an apocalyptic number.

11344221131 is a deficient number, since it is larger than the sum of its proper divisors (391180069).

11344221131 is an equidigital number, since it uses as much as digits as its factorization.

11344221131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 391180068.

The product of its digits is 576, while the sum is 23.

Adding to 11344221131 its reverse (13112244311), we get a palindrome (24456465442).

The spelling of 11344221131 in words is "eleven billion, three hundred forty-four million, two hundred twenty-one thousand, one hundred thirty-one".

Divisors: 1 29 391180039 11344221131