Base | Representation |
---|---|
bin | 10101001000010101… |
… | …10100001111011001 |
3 | 1002021121011202201211 |
4 | 22210022310033121 |
5 | 141213110432213 |
6 | 5113402143121 |
7 | 551056251601 |
oct | 124412641731 |
9 | 32247152654 |
10 | 11344233433 |
11 | 48a1584535 |
12 | 22471b1aa1 |
13 | 10ba341b80 |
14 | 7988b9c01 |
15 | 465dd953d |
hex | 2a42b43d9 |
11344233433 has 16 divisors (see below), whose sum is σ = 13080871440. Its totient is φ = 9744869376.
The previous prime is 11344233359. The next prime is 11344233451. The reversal of 11344233433 is 33433244311.
It can be written as a sum of positive squares in 8 ways, for example, as 236759769 + 11107473664 = 15387^2 + 105392^2 .
It is a cyclic number.
It is not a de Polignac number, because 11344233433 - 225 = 11310679001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11344233395 and 11344233404.
It is not an unprimeable number, because it can be changed into a prime (11344230433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 268710 + ... + 308047.
It is an arithmetic number, because the mean of its divisors is an integer number (817554465).
Almost surely, 211344233433 is an apocalyptic number.
11344233433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11344233433 is a deficient number, since it is larger than the sum of its proper divisors (1736638007).
11344233433 is a wasteful number, since it uses less digits than its factorization.
11344233433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 576876.
The product of its digits is 31104, while the sum is 31.
Adding to 11344233433 its reverse (33433244311), we get a palindrome (44777477744).
The spelling of 11344233433 in words is "eleven billion, three hundred forty-four million, two hundred thirty-three thousand, four hundred thirty-three".
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