Base | Representation |
---|---|
bin | 10101001000010110… |
… | …01100001010001111 |
3 | 1002021121100202010111 |
4 | 22210023030022033 |
5 | 141213122101112 |
6 | 5113404220451 |
7 | 551060140333 |
oct | 124413141217 |
9 | 32247322114 |
10 | 11344331407 |
11 | 48a1641102 |
12 | 224723a727 |
13 | 10ba377646 |
14 | 7989037c3 |
15 | 465e085a7 |
hex | 2a42cc28f |
11344331407 has 2 divisors, whose sum is σ = 11344331408. Its totient is φ = 11344331406.
The previous prime is 11344331399. The next prime is 11344331437. The reversal of 11344331407 is 70413344311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11344331407 - 23 = 11344331399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11344331437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672165703 + 5672165704.
It is an arithmetic number, because the mean of its divisors is an integer number (5672165704).
Almost surely, 211344331407 is an apocalyptic number.
11344331407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344331407 is an equidigital number, since it uses as much as digits as its factorization.
11344331407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 11344331407 its reverse (70413344311), we get a palindrome (81757675718).
The spelling of 11344331407 in words is "eleven billion, three hundred forty-four million, three hundred thirty-one thousand, four hundred seven".
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