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113443514143 is a prime number
BaseRepresentation
bin110100110100111000…
…0101010011100011111
3101211211001222121201221
41221221300222130133
53324313014423033
6124040520114211
711124143650201
oct1515160523437
9354731877657
10113443514143
11441249a7273
1219ba0005967
13a90ba49c3b
1456c267a771
152e3e59812d
hex1a69c2a71f

113443514143 has 2 divisors, whose sum is σ = 113443514144. Its totient is φ = 113443514142.

The previous prime is 113443514089. The next prime is 113443514161. The reversal of 113443514143 is 341415344311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113443514143 - 213 = 113443505951 is a prime.

It is a super-2 number, since 2×1134435141432 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113443514099 and 113443514108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113443514243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56721757071 + 56721757072.

It is an arithmetic number, because the mean of its divisors is an integer number (56721757072).

Almost surely, 2113443514143 is an apocalyptic number.

113443514143 is a deficient number, since it is larger than the sum of its proper divisors (1).

113443514143 is an equidigital number, since it uses as much as digits as its factorization.

113443514143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 34.

Adding to 113443514143 its reverse (341415344311), we get a palindrome (454858858454).

The spelling of 113443514143 in words is "one hundred thirteen billion, four hundred forty-three million, five hundred fourteen thousand, one hundred forty-three".