11344414314053 has 8 divisors (see below), whose sum is σ = 11361754750080. Its totient is φ = 11327084524800.

The previous prime is 11344414314029. The next prime is 11344414314061. The reversal of 11344414314053 is 35041341444311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11344414314053 - 2¹⁴ = 11344414297669 is a prime.

It is a super-2 number, since 2×11344414314053² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11344414313998 and 11344414314016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11344414314253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 527708 + ... + 4792421.

It is an arithmetic number, because the mean of its divisors is an integer number (1420219343760).

Almost surely, 2^{11344414314053} is an apocalyptic number.

It is an amenable number.

11344414314053 is a deficient number, since it is larger than the sum of its proper divisors (17340436027).

11344414314053 is an equidigital number, since it uses as much as digits as its factorization.

11344414314053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5323387.

The product of its (nonzero) digits is 138240, while the sum is 38.

Adding to 11344414314053 its reverse (35041341444311), we get a palindrome (46385755758364).

The spelling of 11344414314053 in words is "eleven trillion, three hundred forty-four billion, four hundred fourteen million, three hundred fourteen thousand, fifty-three".