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1134444143303 = 1774963915947
BaseRepresentation
bin10000100000100010001…
…000111110001011000111
311000110012100210112121222
4100200202020332023013
5122041320200041203
62225053443030555
7144650404054262
oct20404210761307
94013170715558
101134444143303
113a812a164729
12163a4306b45b
1382c92abaa63
143cc9bc3bcd9
151e799833038
hex1082223e2c7

1134444143303 has 4 divisors (see below), whose sum is σ = 1134508077000. Its totient is φ = 1134380209608.

The previous prime is 1134444143299. The next prime is 1134444143369. The reversal of 1134444143303 is 3033414444311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134444143303 - 22 = 1134444143299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1134444143003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31940225 + ... + 31975722.

It is an arithmetic number, because the mean of its divisors is an integer number (283627019250).

Almost surely, 21134444143303 is an apocalyptic number.

1134444143303 is a deficient number, since it is larger than the sum of its proper divisors (63933697).

1134444143303 is an equidigital number, since it uses as much as digits as its factorization.

1134444143303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63933696.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 1134444143303 its reverse (3033414444311), we get a palindrome (4167858587614).

The spelling of 1134444143303 in words is "one trillion, one hundred thirty-four billion, four hundred forty-four million, one hundred forty-three thousand, three hundred three".

Divisors: 1 17749 63915947 1134444143303