Base | Representation |
---|---|
bin | 10101001000100011… |
… | …00100001000110011 |
3 | 1002021201111122102012 |
4 | 22210101210020303 |
5 | 141214034034413 |
6 | 5113504113135 |
7 | 551110300304 |
oct | 124421441063 |
9 | 32251448365 |
10 | 11346002483 |
11 | 48a2582662 |
12 | 22479057ab |
13 | 10ba81114a |
14 | 798c1a7ab |
15 | 4661387a8 |
hex | 2a4464233 |
11346002483 has 2 divisors, whose sum is σ = 11346002484. Its totient is φ = 11346002482.
The previous prime is 11346002477. The next prime is 11346002497. The reversal of 11346002483 is 38420064311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11346002483 - 24 = 11346002467 is a prime.
It is not a weakly prime, because it can be changed into another prime (11346001483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5673001241 + 5673001242.
It is an arithmetic number, because the mean of its divisors is an integer number (5673001242).
Almost surely, 211346002483 is an apocalyptic number.
11346002483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11346002483 is an equidigital number, since it uses as much as digits as its factorization.
11346002483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 11346002483 its reverse (38420064311), we get a palindrome (49766066794).
The spelling of 11346002483 in words is "eleven billion, three hundred forty-six million, two thousand, four hundred eighty-three".
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