Base | Representation |
---|---|
bin | 10000100000110000110… |
… | …111101100100011010101 |
3 | 11000110211120211000201122 |
4 | 100200300313230203111 |
5 | 122042321431213132 |
6 | 2225134151533325 |
7 | 144656464452626 |
oct | 20406067544325 |
9 | 4013746730648 |
10 | 1134691272917 |
11 | 3a8246707884 |
12 | 163ab198a245 |
13 | 83002066ab7 |
14 | 3ccc29aba4d |
15 | 1e7b139b912 |
hex | 10830dec8d5 |
1134691272917 has 4 divisors (see below), whose sum is σ = 1173818558220. Its totient is φ = 1095563987616.
The previous prime is 1134691272889. The next prime is 1134691272919. The reversal of 1134691272917 is 7192721964311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 546595541041 + 588095731876 = 739321^2 + 766874^2 .
It is a cyclic number.
It is not a de Polignac number, because 1134691272917 - 218 = 1134691010773 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134691272919) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19563642608 + ... + 19563642665.
It is an arithmetic number, because the mean of its divisors is an integer number (293454639555).
Almost surely, 21134691272917 is an apocalyptic number.
It is an amenable number.
1134691272917 is a deficient number, since it is larger than the sum of its proper divisors (39127285303).
1134691272917 is an equidigital number, since it uses as much as digits as its factorization.
1134691272917 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39127285302.
The product of its digits is 1143072, while the sum is 53.
The spelling of 1134691272917 in words is "one trillion, one hundred thirty-four billion, six hundred ninety-one million, two hundred seventy-two thousand, nine hundred seventeen".
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