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113477446651 is a prime number
BaseRepresentation
bin110100110101111001…
…0000110101111111011
3101211220102211120101111
41221223302012233323
53324400211243101
6124044131301151
711125035244612
oct1515362065773
9354812746344
10113477446651
1144142073268
1219bab44a7b7
13a915a9ab4a
1456c6d90879
152e4254c251
hex1a6bc86bfb

113477446651 has 2 divisors, whose sum is σ = 113477446652. Its totient is φ = 113477446650.

The previous prime is 113477446633. The next prime is 113477446661. The reversal of 113477446651 is 156644774311.

It is a strong prime.

It is an emirp because it is prime and its reverse (156644774311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113477446651 - 29 = 113477446139 is a prime.

It is a super-4 number, since 4×1134774466514 (a number of 45 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 113477446595 and 113477446604.

It is not a weakly prime, because it can be changed into another prime (113477446601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56738723325 + 56738723326.

It is an arithmetic number, because the mean of its divisors is an integer number (56738723326).

Almost surely, 2113477446651 is an apocalyptic number.

113477446651 is a deficient number, since it is larger than the sum of its proper divisors (1).

113477446651 is an equidigital number, since it uses as much as digits as its factorization.

113477446651 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1693440, while the sum is 49.

The spelling of 113477446651 in words is "one hundred thirteen billion, four hundred seventy-seven million, four hundred forty-six thousand, six hundred fifty-one".