Base | Representation |
---|---|
bin | 110100110110000100… |
… | …0010100101011110011 |
3 | 101211220211210110202101 |
4 | 1221230020110223303 |
5 | 3324403204132044 |
6 | 124044500201231 |
7 | 11125135613125 |
oct | 1515410245363 |
9 | 354824713671 |
10 | 113483270899 |
11 | 44145391099 |
12 | 19bb1399217 |
13 | a917059b4b |
14 | 56c7a69215 |
15 | 2e42ceccd4 |
hex | 1a6c214af3 |
113483270899 has 2 divisors, whose sum is σ = 113483270900. Its totient is φ = 113483270898.
The previous prime is 113483270893. The next prime is 113483270963. The reversal of 113483270899 is 998072384311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113483270899 - 25 = 113483270867 is a prime.
It is not a weakly prime, because it can be changed into another prime (113483270893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56741635449 + 56741635450.
It is an arithmetic number, because the mean of its divisors is an integer number (56741635450).
Almost surely, 2113483270899 is an apocalyptic number.
113483270899 is a deficient number, since it is larger than the sum of its proper divisors (1).
113483270899 is an equidigital number, since it uses as much as digits as its factorization.
113483270899 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 55.
The spelling of 113483270899 in words is "one hundred thirteen billion, four hundred eighty-three million, two hundred seventy thousand, eight hundred ninety-nine".
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