Base | Representation |
---|---|
bin | 1010010100101010110101… |
… | …1011011101111111101111 |
3 | 1111012001212212200100202022 |
4 | 2211022231123131333233 |
5 | 2441430214043131101 |
6 | 40050114353020355 |
7 | 2251011602553611 |
oct | 245125533357757 |
9 | 44161785610668 |
10 | 11350213255151 |
11 | 3686664534a91 |
12 | 13338b75546bb |
13 | 64442223b054 |
14 | 2b34d347adb1 |
15 | 14a3a22d4a1b |
hex | a52ad6ddfef |
11350213255151 has 2 divisors, whose sum is σ = 11350213255152. Its totient is φ = 11350213255150.
The previous prime is 11350213255079. The next prime is 11350213255189. The reversal of 11350213255151 is 15155231205311.
It is a strong prime.
It is an emirp because it is prime and its reverse (15155231205311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11350213255151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11350213255951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5675106627575 + 5675106627576.
It is an arithmetic number, because the mean of its divisors is an integer number (5675106627576).
Almost surely, 211350213255151 is an apocalyptic number.
11350213255151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11350213255151 is an equidigital number, since it uses as much as digits as its factorization.
11350213255151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22500, while the sum is 35.
The spelling of 11350213255151 in words is "eleven trillion, three hundred fifty billion, two hundred thirteen million, two hundred fifty-five thousand, one hundred fifty-one".
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