Base | Representation |
---|---|
bin | 11001110011110100110001… |
… | …101100111110110011010011 |
3 | 112212220200200000011101022202 |
4 | 121303310301230332303103 |
5 | 104334242122240304024 |
6 | 1041230533414553415 |
7 | 32624003114505443 |
oct | 3163646154766323 |
9 | 485820600141282 |
10 | 113512524541139 |
11 | 33194433924509 |
12 | 108935a296886b |
13 | 4b4525397c0c9 |
14 | 200606d5bc123 |
15 | d1cac43bebae |
hex | 673d31b3ecd3 |
113512524541139 has 2 divisors, whose sum is σ = 113512524541140. Its totient is φ = 113512524541138.
The previous prime is 113512524541037. The next prime is 113512524541151. The reversal of 113512524541139 is 931145425215311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113512524541139 - 224 = 113512507763923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113512524541093 and 113512524541102.
It is not a weakly prime, because it can be changed into another prime (113512524541159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56756262270569 + 56756262270570.
It is an arithmetic number, because the mean of its divisors is an integer number (56756262270570).
Almost surely, 2113512524541139 is an apocalyptic number.
113512524541139 is a deficient number, since it is larger than the sum of its proper divisors (1).
113512524541139 is an equidigital number, since it uses as much as digits as its factorization.
113512524541139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648000, while the sum is 47.
The spelling of 113512524541139 in words is "one hundred thirteen trillion, five hundred twelve billion, five hundred twenty-four million, five hundred forty-one thousand, one hundred thirty-nine".
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