Base | Representation |
---|---|
bin | 110100110110111111… |
… | …0100011010000110011 |
3 | 101212000000010001202022 |
4 | 1221231332203100303 |
5 | 3324434122413403 |
6 | 124051524342055 |
7 | 11125663214636 |
oct | 1515576432063 |
9 | 355000101668 |
10 | 113514263603 |
11 | 4416092a3a4 |
12 | 19bbb84492b |
13 | a9205bb920 |
14 | 56cbc15c1d |
15 | 2e458c0d38 |
hex | 1a6dfa3433 |
113514263603 has 4 divisors (see below), whose sum is σ = 122246130048. Its totient is φ = 104782397160.
The previous prime is 113514263581. The next prime is 113514263623. The reversal of 113514263603 is 306362415311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 306362415311 = 75629 ⋅4050859.
It is a cyclic number.
It is not a de Polignac number, because 113514263603 - 210 = 113514262579 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113514263623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4365933203 + ... + 4365933228.
It is an arithmetic number, because the mean of its divisors is an integer number (30561532512).
Almost surely, 2113514263603 is an apocalyptic number.
113514263603 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113514263603 is a deficient number, since it is larger than the sum of its proper divisors (8731866445).
113514263603 is an equidigital number, since it uses as much as digits as its factorization.
113514263603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8731866444.
The product of its (nonzero) digits is 38880, while the sum is 35.
Adding to 113514263603 its reverse (306362415311), we get a palindrome (419876678914).
The spelling of 113514263603 in words is "one hundred thirteen billion, five hundred fourteen million, two hundred sixty-three thousand, six hundred three".
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