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1135145513533 is a prime number
BaseRepresentation
bin10000100001001011111…
…100011111001000111101
311000112000020112211201011
4100201023330133020331
5122044234222413113
62225251215515221
7145003651443403
oct20411374371075
94015006484634
101135145513533
113a845a05a549
12163bb9b28b11
13830751b9a25
143cd27051473
151e7db1c663d
hex1084bf1f23d

1135145513533 has 2 divisors, whose sum is σ = 1135145513534. Its totient is φ = 1135145513532.

The previous prime is 1135145513521. The next prime is 1135145513599. The reversal of 1135145513533 is 3353155415311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 803787557764 + 331357955769 = 896542^2 + 575637^2 .

It is a cyclic number.

It is not a de Polignac number, because 1135145513533 - 217 = 1135145382461 is a prime.

It is a super-2 number, since 2×11351455135332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1135145513833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567572756766 + 567572756767.

It is an arithmetic number, because the mean of its divisors is an integer number (567572756767).

Almost surely, 21135145513533 is an apocalyptic number.

It is an amenable number.

1135145513533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1135145513533 is an equidigital number, since it uses as much as digits as its factorization.

1135145513533 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 202500, while the sum is 40.

The spelling of 1135145513533 in words is "one trillion, one hundred thirty-five billion, one hundred forty-five million, five hundred thirteen thousand, five hundred thirty-three".