Base | Representation |
---|---|
bin | 10101001001010000… |
… | …11111101100100011 |
3 | 1002022010211001010021 |
4 | 22210220133230203 |
5 | 141222103413403 |
6 | 5114241014311 |
7 | 551212344400 |
oct | 124450375443 |
9 | 32263731107 |
10 | 11352013603 |
11 | 48a5a08927 |
12 | 2249924397 |
13 | 10bbb37218 |
14 | 7999432a7 |
15 | 4669248bd |
hex | 2a4a1fb23 |
11352013603 has 12 divisors (see below), whose sum is σ = 13207787832. Its totient is φ = 9728540640.
The previous prime is 11352013577. The next prime is 11352013609. The reversal of 11352013603 is 30631025311.
11352013603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11352013603 - 25 = 11352013571 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11352013609) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 304351 + ... + 339607.
It is an arithmetic number, because the mean of its divisors is an integer number (1100648986).
Almost surely, 211352013603 is an apocalyptic number.
11352013603 is a deficient number, since it is larger than the sum of its proper divisors (1855774229).
11352013603 is an equidigital number, since it uses as much as digits as its factorization.
11352013603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41842 (or 41835 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 11352013603 its reverse (30631025311), we get a palindrome (41983038914).
The spelling of 11352013603 in words is "eleven billion, three hundred fifty-two million, thirteen thousand, six hundred three".
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