11352115 has 4 divisors (see below), whose sum is σ = 13622544. Its totient is φ = 9081688.

The previous prime is 11352083. The next prime is 11352151. The reversal of 11352115 is 51125311.

11352115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51125311 = 881 ⋅58031.

It is a cyclic number.

It is not a de Polignac number, because 11352115 - 2⁵ = 11352083 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11352092 and 11352101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1135207 + ... + 1135216.

It is an arithmetic number, because the mean of its divisors is an integer number (3405636).

Almost surely, 2^11352115 is an apocalyptic number.

11352115 is a deficient number, since it is larger than the sum of its proper divisors (2270429).

11352115 is an equidigital number, since it uses as much as digits as its factorization.

11352115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2270428.

The product of its digits is 150, while the sum is 19.

The square root of 11352115 is about 3369.2899845516. The cubic root of 11352115 is about 224.7461499223.

Adding to 11352115 its reverse (51125311), we get a palindrome (62477426).

The spelling of 11352115 in words is "eleven million, three hundred fifty-two thousand, one hundred fifteen".