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113534523014041 is a prime number
BaseRepresentation
bin11001110100001001010000…
…111010011111101110011001
3112212222210110010011121000101
4121310021100322133232121
5104340122200342422131
61041245012334335401
732625412214444113
oct3164112072375631
9485883403147011
10113534523014041
11331a27a2447828
121089790205a561
134b4734b3b7c8c
1420071590823b3
15d1d4607eac61
hex674250e9fb99

113534523014041 has 2 divisors, whose sum is σ = 113534523014042. Its totient is φ = 113534523014040.

The previous prime is 113534523014027. The next prime is 113534523014047. The reversal of 113534523014041 is 140410325435311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112508364144016 + 1026158870025 = 10606996^2 + 1012995^2 .

It is a cyclic number.

It is not a de Polignac number, because 113534523014041 - 25 = 113534523014009 is a prime.

It is not a weakly prime, because it can be changed into another prime (113534523014047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767261507020 + 56767261507021.

It is an arithmetic number, because the mean of its divisors is an integer number (56767261507021).

Almost surely, 2113534523014041 is an apocalyptic number.

It is an amenable number.

113534523014041 is a deficient number, since it is larger than the sum of its proper divisors (1).

113534523014041 is an equidigital number, since it uses as much as digits as its factorization.

113534523014041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 113534523014041 its reverse (140410325435311), we get a palindrome (253944848449352).

The spelling of 113534523014041 in words is "one hundred thirteen trillion, five hundred thirty-four billion, five hundred twenty-three million, fourteen thousand, forty-one".