Base | Representation |
---|---|
bin | 11001110100001010001100… |
… | …011010110110100111010111 |
3 | 112212222220000200201102102221 |
4 | 121310022030122312213113 |
5 | 104340131221431232101 |
6 | 1041245255400243211 |
7 | 32625446026253623 |
oct | 3164121432664727 |
9 | 485886020642387 |
10 | 113535521352151 |
11 | 331a3164a35a48 |
12 | 10897b40470507 |
13 | 4b4747a1928a2 |
14 | 20072118ba183 |
15 | d1d4bd29eaa1 |
hex | 67428c6b69d7 |
113535521352151 has 2 divisors, whose sum is σ = 113535521352152. Its totient is φ = 113535521352150.
The previous prime is 113535521352083. The next prime is 113535521352161. The reversal of 113535521352151 is 151253125535311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113535521352151 - 217 = 113535521221079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113535521352098 and 113535521352107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113535521352161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767760676075 + 56767760676076.
It is an arithmetic number, because the mean of its divisors is an integer number (56767760676076).
Almost surely, 2113535521352151 is an apocalyptic number.
113535521352151 is a deficient number, since it is larger than the sum of its proper divisors (1).
113535521352151 is an equidigital number, since it uses as much as digits as its factorization.
113535521352151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 337500, while the sum is 43.
Adding to 113535521352151 its reverse (151253125535311), we get a palindrome (264788646887462).
The spelling of 113535521352151 in words is "one hundred thirteen trillion, five hundred thirty-five billion, five hundred twenty-one million, three hundred fifty-two thousand, one hundred fifty-one".
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