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113540034244151 = 964463117723577
BaseRepresentation
bin11001110100001110011001…
…011010001010111000110111
3112220000022200012112002110002
4121310032121122022320313
5104340214442231303101
61041251323251221515
732625665615230304
oct3164163132127067
9486008605462402
10113540034244151
11331a5070391559
121089899b8a789b
134b47a19131398
14200751cdc00ab
15d1d684587d6b
hex67439968ae37

113540034244151 has 4 divisors (see below), whose sum is σ = 113540152932192. Its totient is φ = 113539915556112.

The previous prime is 113540034244139. The next prime is 113540034244159. The reversal of 113540034244151 is 151442430045311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113540034244151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113540034244159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57897326 + ... + 59826251.

It is an arithmetic number, because the mean of its divisors is an integer number (28385038233048).

Almost surely, 2113540034244151 is an apocalyptic number.

113540034244151 is a deficient number, since it is larger than the sum of its proper divisors (118688041).

113540034244151 is an equidigital number, since it uses as much as digits as its factorization.

113540034244151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118688040.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 113540034244151 its reverse (151442430045311), we get a palindrome (264982464289462).

The spelling of 113540034244151 in words is "one hundred thirteen trillion, five hundred forty billion, thirty-four million, two hundred forty-four thousand, one hundred fifty-one".

Divisors: 1 964463 117723577 113540034244151