113540042543331 has 4 divisors (see below), whose sum is σ = 151386723391112. Its totient is φ = 75693361695552.

The previous prime is 113540042543329. The next prime is 113540042543339. The reversal of 113540042543331 is 133345240045311.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 113540042543331 - 2¹ = 113540042543329 is a prime.

It is a super-2 number, since 2×113540042543331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113540042543331.

It is not an unprimeable number, because it can be changed into a prime (113540042543339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18923340423886 + ... + 18923340423891.

It is an arithmetic number, because the mean of its divisors is an integer number (37846680847778).

Almost surely, 2^{113540042543331} is an apocalyptic number.

113540042543331 is a deficient number, since it is larger than the sum of its proper divisors (37846680847781).

113540042543331 is an equidigital number, since it uses as much as digits as its factorization.

113540042543331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37846680847780.

The product of its (nonzero) digits is 259200, while the sum is 39.

Adding to 113540042543331 its reverse (133345240045311), we get a palindrome (246885282588642).

The spelling of 113540042543331 in words is "one hundred thirteen trillion, five hundred forty billion, forty-two million, five hundred forty-three thousand, three hundred thirty-one".