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113541033314 = 256770516657
BaseRepresentation
bin110100110111110010…
…0101010110101100010
3101212001212111002220002
41221233210222311202
53330013001031224
6124054322220002
711126436600512
oct1515744526542
9355055432802
10113541033314
1144174a53925
121a0087b4602
13a9260024a7
1456d15c3842
152e47e0c9ae
hex1a6f92ad62

113541033314 has 4 divisors (see below), whose sum is σ = 170311549974. Its totient is φ = 56770516656.

The previous prime is 113541033313. The next prime is 113541033329. The reversal of 113541033314 is 413330145311.

It is a happy number.

113541033314 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 88265439025 + 25275594289 = 297095^2 + 158983^2 .

It is not an unprimeable number, because it can be changed into a prime (113541033313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28385258327 + ... + 28385258330.

Almost surely, 2113541033314 is an apocalyptic number.

113541033314 is a deficient number, since it is larger than the sum of its proper divisors (56770516660).

113541033314 is an equidigital number, since it uses as much as digits as its factorization.

113541033314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56770516659.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 113541033314 its reverse (413330145311), we get a palindrome (526871178625).

The spelling of 113541033314 in words is "one hundred thirteen billion, five hundred forty-one million, thirty-three thousand, three hundred fourteen".

Divisors: 1 2 56770516657 113541033314