Base | Representation |
---|---|
bin | 11001110100001111011001… |
… | …101101110000101001010111 |
3 | 112220000102110101121201202111 |
4 | 121310033121231300221113 |
5 | 104340224144424340432 |
6 | 1041252022311251451 |
7 | 32626034425440031 |
oct | 3164173155605127 |
9 | 486012411551674 |
10 | 113541113121367 |
11 | 331a5574389a18 |
12 | 10899041079b87 |
13 | 4b47b5b7c7879 |
14 | 20075c23c0c51 |
15 | d1d6e914a347 |
hex | 6743d9b70a57 |
113541113121367 has 2 divisors, whose sum is σ = 113541113121368. Its totient is φ = 113541113121366.
The previous prime is 113541113121283. The next prime is 113541113121379. The reversal of 113541113121367 is 763121311145311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113541113121367 - 211 = 113541113119319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113541113125367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56770556560683 + 56770556560684.
It is an arithmetic number, because the mean of its divisors is an integer number (56770556560684).
Almost surely, 2113541113121367 is an apocalyptic number.
113541113121367 is a deficient number, since it is larger than the sum of its proper divisors (1).
113541113121367 is an equidigital number, since it uses as much as digits as its factorization.
113541113121367 is an evil number, because the sum of its binary digits is even.
The product of its digits is 45360, while the sum is 40.
Adding to 113541113121367 its reverse (763121311145311), we get a palindrome (876662424266678).
The spelling of 113541113121367 in words is "one hundred thirteen trillion, five hundred forty-one billion, one hundred thirteen million, one hundred twenty-one thousand, three hundred sixty-seven".
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