Base | Representation |
---|---|
bin | 1010010100111001111000… |
… | …1010100100101001011011 |
3 | 1111012110022100112201022222 |
4 | 2211032132022210221123 |
5 | 2442012002021310003 |
6 | 40052023232134255 |
7 | 2251213644511541 |
oct | 245163612445133 |
9 | 44173270481288 |
10 | 11354252135003 |
11 | 3688347364218 |
12 | 133464409738b |
13 | 644916c2349b |
14 | 2b3797a31d91 |
15 | 14a53bb89c38 |
hex | a539e2a4a5b |
11354252135003 has 2 divisors, whose sum is σ = 11354252135004. Its totient is φ = 11354252135002.
The previous prime is 11354252134943. The next prime is 11354252135047. The reversal of 11354252135003 is 30053125245311.
It is a happy number.
11354252135003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11354252135003 is a prime.
It is not a weakly prime, because it can be changed into another prime (11354252135903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677126067501 + 5677126067502.
It is an arithmetic number, because the mean of its divisors is an integer number (5677126067502).
Almost surely, 211354252135003 is an apocalyptic number.
11354252135003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11354252135003 is an equidigital number, since it uses as much as digits as its factorization.
11354252135003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 11354252135003 in words is "eleven trillion, three hundred fifty-four billion, two hundred fifty-two million, one hundred thirty-five thousand, three".
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