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1135435132001 = 7558991502099
BaseRepresentation
bin10000100001011101001…
…101010010110001100001
311000112202102111222120002
4100201131031102301201
5122100332343211001
62225340043225345
7145014066244202
oct20413515226141
94015672458502
101135435132001
113a8598593155
1216407ab18255
13830c01c13c1
143cd536c15a9
151e80683446b
hex1085d352c61

1135435132001 has 4 divisors (see below), whose sum is σ = 1135437390000. Its totient is φ = 1135432874004.

The previous prime is 1135435131989. The next prime is 1135435132049. The reversal of 1135435132001 is 1002315345311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1135435132001 - 226 = 1135368023137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1135435152001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4850 + ... + 1506948.

It is an arithmetic number, because the mean of its divisors is an integer number (283859347500).

Almost surely, 21135435132001 is an apocalyptic number.

It is an amenable number.

1135435132001 is a deficient number, since it is larger than the sum of its proper divisors (2257999).

1135435132001 is an equidigital number, since it uses as much as digits as its factorization.

1135435132001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2257998.

The product of its (nonzero) digits is 5400, while the sum is 29.

The spelling of 1135435132001 in words is "one trillion, one hundred thirty-five billion, four hundred thirty-five million, one hundred thirty-two thousand, one".

Divisors: 1 755899 1502099 1135435132001