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11354415203987 is a prime number
BaseRepresentation
bin1010010100111010011111…
…1000101000011010010011
31111012110201201101110220222
42211032213320220122103
52442012320243011422
640052051335223255
72251220664542402
oct245164770503223
944173651343828
1011354415203987
113688420412379
12133468a817b2b
13644941949acb
142b37b155d639
1514a54b14b842
hexa53a7e28693

11354415203987 has 2 divisors, whose sum is σ = 11354415203988. Its totient is φ = 11354415203986.

The previous prime is 11354415203891. The next prime is 11354415204037. The reversal of 11354415203987 is 78930251445311.

It is a happy number.

11354415203987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11354415203987 - 230 = 11353341462163 is a prime.

It is a super-2 number, since 2×113544152039872 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11354415206987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677207601993 + 5677207601994.

It is an arithmetic number, because the mean of its divisors is an integer number (5677207601994).

Almost surely, 211354415203987 is an apocalyptic number.

11354415203987 is a deficient number, since it is larger than the sum of its proper divisors (1).

11354415203987 is an equidigital number, since it uses as much as digits as its factorization.

11354415203987 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3628800, while the sum is 53.

The spelling of 11354415203987 in words is "eleven trillion, three hundred fifty-four billion, four hundred fifteen million, two hundred three thousand, nine hundred eighty-seven".