Base | Representation |
---|---|
bin | 1010010100111010011111… |
… | …1000101000011010010011 |
3 | 1111012110201201101110220222 |
4 | 2211032213320220122103 |
5 | 2442012320243011422 |
6 | 40052051335223255 |
7 | 2251220664542402 |
oct | 245164770503223 |
9 | 44173651343828 |
10 | 11354415203987 |
11 | 3688420412379 |
12 | 133468a817b2b |
13 | 644941949acb |
14 | 2b37b155d639 |
15 | 14a54b14b842 |
hex | a53a7e28693 |
11354415203987 has 2 divisors, whose sum is σ = 11354415203988. Its totient is φ = 11354415203986.
The previous prime is 11354415203891. The next prime is 11354415204037. The reversal of 11354415203987 is 78930251445311.
It is a happy number.
11354415203987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11354415203987 - 230 = 11353341462163 is a prime.
It is a super-2 number, since 2×113544152039872 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11354415206987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677207601993 + 5677207601994.
It is an arithmetic number, because the mean of its divisors is an integer number (5677207601994).
Almost surely, 211354415203987 is an apocalyptic number.
11354415203987 is a deficient number, since it is larger than the sum of its proper divisors (1).
11354415203987 is an equidigital number, since it uses as much as digits as its factorization.
11354415203987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 53.
The spelling of 11354415203987 in words is "eleven trillion, three hundred fifty-four billion, four hundred fifteen million, two hundred three thousand, nine hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •