Base | Representation |
---|---|
bin | 10000100001011111010… |
… | …110111000110001110001 |
3 | 11000112211221101111110111 |
4 | 100201133112320301301 |
5 | 122100421111421033 |
6 | 2225343412301321 |
7 | 145015014651604 |
oct | 20413726706161 |
9 | 4015757344414 |
10 | 1135471201393 |
11 | 3a8606989671 |
12 | 16408b011841 |
13 | 830c780cb39 |
14 | 3cd583d033b |
15 | 1e809aab7cd |
hex | 1085f5b8c71 |
1135471201393 has 2 divisors, whose sum is σ = 1135471201394. Its totient is φ = 1135471201392.
The previous prime is 1135471201391. The next prime is 1135471201429. The reversal of 1135471201393 is 3931021745311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1120987560289 + 14483641104 = 1058767^2 + 120348^2 .
It is a cyclic number.
It is not a de Polignac number, because 1135471201393 - 21 = 1135471201391 is a prime.
Together with 1135471201391, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1135471201391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567735600696 + 567735600697.
It is an arithmetic number, because the mean of its divisors is an integer number (567735600697).
Almost surely, 21135471201393 is an apocalyptic number.
It is an amenable number.
1135471201393 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135471201393 is an equidigital number, since it uses as much as digits as its factorization.
1135471201393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 40.
The spelling of 1135471201393 in words is "one trillion, one hundred thirty-five billion, four hundred seventy-one million, two hundred one thousand, three hundred ninety-three".
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