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113551121 is a prime number
BaseRepresentation
bin1101100010010…
…10011100010001
321220122222212002
412301022130101
5213032113441
615133443345
72546111555
oct661123421
9256588762
10113551121
1159107702
1232040555
131a6a9818
141111b865
159e7eb9b
hex6c4a711

113551121 has 2 divisors, whose sum is σ = 113551122. Its totient is φ = 113551120.

The previous prime is 113551117. The next prime is 113551147. The reversal of 113551121 is 121155311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111534721 + 2016400 = 10561^2 + 1420^2 .

It is a cyclic number.

It is not a de Polignac number, because 113551121 - 22 = 113551117 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113551093 and 113551102.

It is not a weakly prime, because it can be changed into another prime (113551111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56775560 + 56775561.

It is an arithmetic number, because the mean of its divisors is an integer number (56775561).

Almost surely, 2113551121 is an apocalyptic number.

It is an amenable number.

113551121 is a deficient number, since it is larger than the sum of its proper divisors (1).

113551121 is an equidigital number, since it uses as much as digits as its factorization.

113551121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 150, while the sum is 20.

The square root of 113551121 is about 10656.0368336450. The cubic root of 113551121 is about 484.2435097874.

The spelling of 113551121 in words is "one hundred thirteen million, five hundred fifty-one thousand, one hundred twenty-one".