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113551520163 = 337850506721
BaseRepresentation
bin110100111000000110…
…0101011000110100011
3101212002121012220010220
41221300030223012203
53330023142121123
6124055335054123
711126624665434
oct1516014530643
9355077186126
10113551520163
114417a966844
121a010211343
13a928234823
1456d2b5348b
152e48ccece3
hex1a7032b1a3

113551520163 has 4 divisors (see below), whose sum is σ = 151402026888. Its totient is φ = 75701013440.

The previous prime is 113551520113. The next prime is 113551520167. The reversal of 113551520163 is 361025155311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113551520163 - 233 = 104961585571 is a prime.

It is not an unprimeable number, because it can be changed into a prime (113551520167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18925253358 + ... + 18925253363.

It is an arithmetic number, because the mean of its divisors is an integer number (37850506722).

Almost surely, 2113551520163 is an apocalyptic number.

113551520163 is a deficient number, since it is larger than the sum of its proper divisors (37850506725).

113551520163 is an equidigital number, since it uses as much as digits as its factorization.

113551520163 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37850506724.

The product of its (nonzero) digits is 13500, while the sum is 33.

Adding to 113551520163 its reverse (361025155311), we get a palindrome (474576675474).

The spelling of 113551520163 in words is "one hundred thirteen billion, five hundred fifty-one million, five hundred twenty thousand, one hundred sixty-three".

Divisors: 1 3 37850506721 113551520163