Base | Representation |
---|---|
bin | 11001110100011010000000… |
… | …001100111010101000110111 |
3 | 112220001111211200222010121121 |
4 | 121310122000030322220313 |
5 | 104340421003014204312 |
6 | 1041301144023124411 |
7 | 32626616466401242 |
oct | 3164320014725067 |
9 | 486044750863547 |
10 | 113552496241207 |
11 | 331aa385903381 |
12 | 1089b2992a3707 |
13 | 4b48c53c0343a |
14 | 2007d82100259 |
15 | d1db63666707 |
hex | 67468033aa37 |
113552496241207 has 2 divisors, whose sum is σ = 113552496241208. Its totient is φ = 113552496241206.
The previous prime is 113552496241073. The next prime is 113552496241291. The reversal of 113552496241207 is 702142694255311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113552496241207 - 211 = 113552496239159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113552496241507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776248120603 + 56776248120604.
It is an arithmetic number, because the mean of its divisors is an integer number (56776248120604).
Almost surely, 2113552496241207 is an apocalyptic number.
113552496241207 is a deficient number, since it is larger than the sum of its proper divisors (1).
113552496241207 is an equidigital number, since it uses as much as digits as its factorization.
113552496241207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 52.
The spelling of 113552496241207 in words is "one hundred thirteen trillion, five hundred fifty-two billion, four hundred ninety-six million, two hundred forty-one thousand, two hundred seven".
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