Base | Representation |
---|---|
bin | 11001110100011010000010… |
… | …011011010000100010001101 |
3 | 112220001111221022011212222120 |
4 | 121310122002123100202031 |
5 | 104340421042042232331 |
6 | 1041301151435003153 |
7 | 32626620431511636 |
oct | 3164320233204215 |
9 | 486044838155876 |
10 | 113552533555341 |
11 | 331aa3a497a001 |
12 | 1089b2a98994b9 |
13 | 4b48c5b8695ca |
14 | 2007d8705488d |
15 | d1db66a87796 |
hex | 6746826d088d |
113552533555341 has 16 divisors (see below), whose sum is σ = 161479601184384. Its totient is φ = 70728585373184.
The previous prime is 113552533555339. The next prime is 113552533555379. The reversal of 113552533555341 is 143555335255311.
It is not a de Polignac number, because 113552533555341 - 21 = 113552533555339 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113552533555441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8125979385 + ... + 8125993358.
It is an arithmetic number, because the mean of its divisors is an integer number (10092475074024).
Almost surely, 2113552533555341 is an apocalyptic number.
It is an amenable number.
113552533555341 is a deficient number, since it is larger than the sum of its proper divisors (47927067629043).
113552533555341 is a wasteful number, since it uses less digits than its factorization.
113552533555341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16251972900.
The product of its digits is 10125000, while the sum is 51.
The spelling of 113552533555341 in words is "one hundred thirteen trillion, five hundred fifty-two billion, five hundred thirty-three million, five hundred fifty-five thousand, three hundred forty-one".
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