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1135533042541 is a prime number
BaseRepresentation
bin10000100001100011000…
…010110010101101101101
311000120000020202100120101
4100201203002302231231
5122101032424330131
62225353501551101
7145016365414522
oct20414302625555
94016006670511
101135533042541
113a8638887857
121640a7875491
1383107582b31
143cd626cb149
151e810224c61
hex108630b2b6d

1135533042541 has 2 divisors, whose sum is σ = 1135533042542. Its totient is φ = 1135533042540.

The previous prime is 1135533042533. The next prime is 1135533042569. The reversal of 1135533042541 is 1452403355311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1005678037225 + 129855005316 = 1002835^2 + 360354^2 .

It is a cyclic number.

It is not a de Polignac number, because 1135533042541 - 23 = 1135533042533 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1135533042541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1135533042521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567766521270 + 567766521271.

It is an arithmetic number, because the mean of its divisors is an integer number (567766521271).

Almost surely, 21135533042541 is an apocalyptic number.

It is an amenable number.

1135533042541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1135533042541 is an equidigital number, since it uses as much as digits as its factorization.

1135533042541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 1135533042541 its reverse (1452403355311), we get a palindrome (2587936397852).

The spelling of 1135533042541 in words is "one trillion, one hundred thirty-five billion, five hundred thirty-three million, forty-two thousand, five hundred forty-one".