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113553452440301 is a prime number
BaseRepresentation
bin11001110100011010111001…
…001100100001101011101101
3112220001121022100020002011212
4121310122321030201223231
5104340424432311042201
61041301422541524205
732626652260063556
oct3164327114415355
9486047270202155
10113553452440301
11331aa82662a965
121089b505573665
134b49077045a13
1420080330c932d
15d1dbbc594abb
hex6746b9321aed

113553452440301 has 2 divisors, whose sum is σ = 113553452440302. Its totient is φ = 113553452440300.

The previous prime is 113553452440273. The next prime is 113553452440339. The reversal of 113553452440301 is 103044254355311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111774563377801 + 1778889062500 = 10572349^2 + 1333750^2 .

It is a cyclic number.

It is not a de Polignac number, because 113553452440301 - 226 = 113553385331437 is a prime.

It is a super-3 number, since 3×1135534524403013 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113553452440601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776726220150 + 56776726220151.

It is an arithmetic number, because the mean of its divisors is an integer number (56776726220151).

Almost surely, 2113553452440301 is an apocalyptic number.

It is an amenable number.

113553452440301 is a deficient number, since it is larger than the sum of its proper divisors (1).

113553452440301 is an equidigital number, since it uses as much as digits as its factorization.

113553452440301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 41.

The spelling of 113553452440301 in words is "one hundred thirteen trillion, five hundred fifty-three billion, four hundred fifty-two million, four hundred forty thousand, three hundred one".