Base | Representation |
---|---|
bin | 11001110100011010111001… |
… | …001100111010001010000111 |
3 | 112220001121022100102011200211 |
4 | 121310122321030322022013 |
5 | 104340424432322244201 |
6 | 1041301422544020251 |
7 | 32626652260662052 |
oct | 3164327114721207 |
9 | 486047270364624 |
10 | 113553452540551 |
11 | 331aa826699211 |
12 | 1089b505601687 |
13 | 4b4907707c53a |
14 | 2008033113a99 |
15 | d1dbbc5b4651 |
hex | 6746b933a287 |
113553452540551 has 2 divisors, whose sum is σ = 113553452540552. Its totient is φ = 113553452540550.
The previous prime is 113553452540501. The next prime is 113553452540579. The reversal of 113553452540551 is 155045254355311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113553452540551 - 217 = 113553452409479 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113553452540495 and 113553452540504.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113553452540501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776726270275 + 56776726270276.
It is an arithmetic number, because the mean of its divisors is an integer number (56776726270276).
Almost surely, 2113553452540551 is an apocalyptic number.
113553452540551 is a deficient number, since it is larger than the sum of its proper divisors (1).
113553452540551 is an equidigital number, since it uses as much as digits as its factorization.
113553452540551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500000, while the sum is 49.
The spelling of 113553452540551 in words is "one hundred thirteen trillion, five hundred fifty-three billion, four hundred fifty-two million, five hundred forty thousand, five hundred fifty-one".
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