Base | Representation |
---|---|
bin | 11001110100011010111101… |
… | …111101001110001000000011 |
3 | 112220001121111220112002110021 |
4 | 121310122331331032020003 |
5 | 104340430113233022430 |
6 | 1041301434513514311 |
7 | 32626654250023045 |
oct | 3164327575161003 |
9 | 486047456462407 |
10 | 113553532314115 |
11 | 331aa867725283 |
12 | 1089b528272997 |
13 | 4b4908a76082a |
14 | 200803d95ba95 |
15 | d1dbc45c107a |
hex | 6746bdf4e203 |
113553532314115 has 4 divisors (see below), whose sum is σ = 136264238776944. Its totient is φ = 90842825851288.
The previous prime is 113553532314083. The next prime is 113553532314119. The reversal of 113553532314115 is 511413235355311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113553532314115 - 25 = 113553532314083 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113553532314119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11355353231407 + ... + 11355353231416.
It is an arithmetic number, because the mean of its divisors is an integer number (34066059694236).
Almost surely, 2113553532314115 is an apocalyptic number.
113553532314115 is a deficient number, since it is larger than the sum of its proper divisors (22710706462829).
113553532314115 is an equidigital number, since it uses as much as digits as its factorization.
113553532314115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22710706462828.
The product of its digits is 405000, while the sum is 43.
Adding to 113553532314115 its reverse (511413235355311), we get a palindrome (624966767669426).
The spelling of 113553532314115 in words is "one hundred thirteen trillion, five hundred fifty-three billion, five hundred thirty-two million, three hundred fourteen thousand, one hundred fifteen".
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