Base | Representation |
---|---|
bin | 11001110100011011100001… |
… | …101010010100101011110101 |
3 | 112220001200001122200202111221 |
4 | 121310123201222110223311 |
5 | 104340432330110340041 |
6 | 1041302014153030341 |
7 | 32630005142454211 |
oct | 3164334152245365 |
9 | 486050048622457 |
10 | 113554131340021 |
11 | 33200044878309 |
12 | 1089b6749b53b1 |
13 | 4b491548a7c28 |
14 | 200809932d941 |
15 | d1dc0be9a2d1 |
hex | 6746e1a94af5 |
113554131340021 has 2 divisors, whose sum is σ = 113554131340022. Its totient is φ = 113554131340020.
The previous prime is 113554131339949. The next prime is 113554131340073. The reversal of 113554131340021 is 120043131455311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 98443504296900 + 15110627043121 = 9921870^2 + 3887239^2 .
It is a cyclic number.
It is not a de Polignac number, because 113554131340021 - 219 = 113554130815733 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113554131346021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777065670010 + 56777065670011.
It is an arithmetic number, because the mean of its divisors is an integer number (56777065670011).
Almost surely, 2113554131340021 is an apocalyptic number.
It is an amenable number.
113554131340021 is a deficient number, since it is larger than the sum of its proper divisors (1).
113554131340021 is an equidigital number, since it uses as much as digits as its factorization.
113554131340021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 113554131340021 its reverse (120043131455311), we get a palindrome (233597262795332).
The spelling of 113554131340021 in words is "one hundred thirteen trillion, five hundred fifty-four billion, one hundred thirty-one million, three hundred forty thousand, twenty-one".
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